Pert estimate question
Here is the question i am confused how to calculate with the information gave:
A project manager has been asked by the client to meet the promise date of the project. The project manager analyzes the schedule before promising a date to the customer. The project manager uses the program evaluation and review technique to evaluate the project schedule. She decides that based on the PERT calculations she can promise a delivery date of June 30. The expected value of the project completion date is May 30. If the project manager is willing to accept a 5% probability that the project will be delivered later than June 30, what is the standard deviation of the duration of the activities on the critical path? Assume a five-day workweek.
a. Ten days
b. Fifteen days
c. One-half month
d. One month
This i found on the PM question bank, with no explanation.
Thank you all for the helpful info.
ChandraR
Tue, 03/02/2010 - 23:17
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Probability of failure to
Probability of failure to meet the dead line = Probability of slippage=5%=0.05
Probabilty of success to meet the dead line=1-Prob. failure = 1-0.05=95%
95% falls in the 2 sigma region from mean.
We have float of 1 month ( June 30 - May 30).
2 sigma = 1 month
1 sigma = 1/2 month
Chandra
cplusplus
Wed, 03/03/2010 - 01:26
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Pert estimate question
Thank you chandra, i know for sure you have the knowledge.
Question: how did you get the float 30 days?
ChandraR
Wed, 03/03/2010 - 01:30
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Expected Value of
Expected Value of completion= May 30
Promised Delivery Date to the customer: June 30
The difference is the Float
Chandra
pkukilla
Wed, 03/03/2010 - 10:34
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Reg Pert Estimate
Deviation =2 sigma since confidence is 95%
2SD= 4 weeks since (expected date+4 weeks = expected date+ SD*2 )
SD=4 weeks/2 = 2 weeks or 1/2 month so the answer is C
cplusplus
Thu, 03/04/2010 - 18:56
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Standard deviation
Preetham,
I am really having difficulty understanding the standard deviation solution you gave,
Is it possible, can you explain with little more steps.
I am looking at SD = (P-O)/6 as the formula to get the standard deviation.
Thank you very much for the helpful info.
ChandraR
Thu, 03/04/2010 - 20:05
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Look at Normal Distribution
Look at Normal Distribution ( Bell Shaped) curve. The middle point is your Expected Value (Xbar). Your data's mean falls at this location and the data's scatter gets on either side of this. Suppose you want to machine a rod to 50 mm radius and on 10 samples you achieve 50.2, 48.3, 50.1 etc. Ideally you want to be as close to mean as possible i.e. less scatter, less deviation from the mean and the mean as close as possible to the specification you are asked by customer/design drawing etc to get. Now suppose your standard deviation is: 0.5. If all the parts you produced follow the normal distribution, 68% of your measurements be :within 1 SD from mean. (X bar + 1 SD) If you are able to bring 95% of the parts within 50+/- 2 SD, If you are able to achieve 99.99% of parts within Xbar+/-3 SD ( Six Sigma), your process is robust. Your rejection rate is very very low some 3 defects per 1 million parts you produced.
In this case you allow 5% slippage i.e. you want to meet the scheduled delivery date with a 95% confidence level which is 2 SDs from the mean(Xbar)
So Xbar+2 SD=X bar + 4 weeks ( From May 30 to June 30)
2 SD = 4 weeks
SD=2 weeks.
SD=(P-O)/6 works if you are given Pessimistic estimate and Optimistic Estimate. Otherwise you have to assume Normal Distribution and use the 5% probability for failure to meet the dead line.
Chandra
cplusplus
Thu, 03/04/2010 - 20:40
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Thanks a lot Chandra, now i
Thanks a lot Chandra, now i am getting it.
1 SD represents 68%
2 SD represents 95%
3 SD represents 99%
In this case 95%, it is 2SD = 4 weeks
sd = 4 weeks / 2 = 2 weeks.
sd = One half month.
Thank yoo,
Raj
pkukilla
Thu, 03/04/2010 - 20:39
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Imagine that you are in
Imagine that you are in the middle and you are moving to right. SD is how far you have deviated from the mean .
ML+4 weeks= New estimate-->(1)
ML+2SD = New Estimate -->(2) [ 2SD =95% confidence]
Deducing (1) and (2) --> SD = 2weeks
cplusplus
Fri, 03/05/2010 - 00:33
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I don't remember where I
Preetham, Thanks.
Is it possible can we exchange questions?
My email: miami3456@yahoo.com
Can you please email your id.
Raj
pmalik
Fri, 09/22/2017 - 07:59
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PERT Estimate
You should solve the Q by considering 2 sigma deviation from the mean.
For more explanations and help in answering your question you can read the following articles:
How to use PERT, CPM and Standard Deviation Together?
What is the Use of Standard Deviation?
3-Point Estimate is Different From PERT
cubone
Wed, 04/11/2018 - 07:18
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Thank you for sharing this
Thank you for sharing this article. I really enjoyed reading it.
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